10100412441113 has 2 divisors, whose sum is σ = 10100412441114. Its totient is φ = 10100412441112.

The previous prime is 10100412441107. The next prime is 10100412441169. The reversal of 10100412441113 is 31114421400101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6793513834969 + 3306898606144 = 2606437^2 + 1818488^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10100412441113 is a prime.

It is not a weakly prime, because it can be changed into another prime (10100412441103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050206220556 + 5050206220557.

It is an arithmetic number, because the mean of its divisors is an integer number (5050206220557).

Almost surely, 2^{10100412441113} is an apocalyptic number.

It is an amenable number.

10100412441113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100412441113 is an equidigital number, since it uses as much as digits as its factorization.

10100412441113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 10100412441113 its reverse (31114421400101), we get a palindrome (41214833841214).

The spelling of 10100412441113 in words is "ten trillion, one hundred billion, four hundred twelve million, four hundred forty-one thousand, one hundred thirteen".