1010054411 has 2 divisors, whose sum is σ = 1010054412. Its totient is φ = 1010054410.

The previous prime is 1010054399. The next prime is 1010054447. The reversal of 1010054411 is 1144500101.

It is a weak prime.

It is an emirp because it is prime and its reverse (1144500101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1010054411 - 2¹⁴ = 1010038027 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1010054411.

It is not a weakly prime, because it can be changed into another prime (1010054471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505027205 + 505027206.

It is an arithmetic number, because the mean of its divisors is an integer number (505027206).

Almost surely, 2^1010054411 is an apocalyptic number.

1010054411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010054411 is an equidigital number, since it uses as much as digits as its factorization.

1010054411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 17.

The square root of 1010054411 is about 31781.3531964893. The cubic root of 1010054411 is about 1003.3403003040.

Adding to 1010054411 its reverse (1144500101), we get a palindrome (2154554512).

The spelling of 1010054411 in words is "one billion, ten million, fifty-four thousand, four hundred eleven".