101011100111401 has 2 divisors, whose sum is σ = 101011100111402. Its totient is φ = 101011100111400.

The previous prime is 101011100111351. The next prime is 101011100111443. The reversal of 101011100111401 is 104111001110101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84964057584025 + 16047042527376 = 9217595^2 + 4005876^2 .

It is an emirp because it is prime and its reverse (104111001110101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101011100111401 is a prime.

It is a super-2 number, since 2×101011100111401² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101011100114401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505550055700 + 50505550055701.

It is an arithmetic number, because the mean of its divisors is an integer number (50505550055701).

Almost surely, 2^{101011100111401} is an apocalyptic number.

It is an amenable number.

101011100111401 is a deficient number, since it is larger than the sum of its proper divisors (1).

101011100111401 is an equidigital number, since it uses as much as digits as its factorization.

101011100111401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 101011100111401 its reverse (104111001110101), we get a palindrome (205122101221502).

The spelling of 101011100111401 in words is "one hundred one trillion, eleven billion, one hundred million, one hundred eleven thousand, four hundred one".