Base | Representation |
---|---|
bin | 10010110100001001… |
… | …01011100110110001 |
3 | 222001222000121122021 |
4 | 21122010223212301 |
5 | 131141341024332 |
6 | 4350153511441 |
7 | 505213012561 |
oct | 113204534661 |
9 | 28058017567 |
10 | 10101111217 |
11 | 43138a53aa |
12 | 1b5aa12581 |
13 | c4c92c9b2 |
14 | 6bb762da1 |
15 | 3e1bd1c97 |
hex | 25a12b9b1 |
10101111217 has 2 divisors, whose sum is σ = 10101111218. Its totient is φ = 10101111216.
The previous prime is 10101111211. The next prime is 10101111253. The reversal of 10101111217 is 71211110101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7787886001 + 2313225216 = 88249^2 + 48096^2 .
It is an emirp because it is prime and its reverse (71211110101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10101111217 - 211 = 10101109169 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10101111217.
It is not a weakly prime, because it can be changed into another prime (10101111211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050555608 + 5050555609.
It is an arithmetic number, because the mean of its divisors is an integer number (5050555609).
Almost surely, 210101111217 is an apocalyptic number.
It is an amenable number.
10101111217 is a deficient number, since it is larger than the sum of its proper divisors (1).
10101111217 is an equidigital number, since it uses as much as digits as its factorization.
10101111217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 16.
Adding to 10101111217 its reverse (71211110101), we get a palindrome (81312221318).
The spelling of 10101111217 in words is "ten billion, one hundred one million, one hundred eleven thousand, two hundred seventeen".
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