1010185648313 has 2 divisors, whose sum is σ = 1010185648314. Its totient is φ = 1010185648312.

The previous prime is 1010185648273. The next prime is 1010185648333. The reversal of 1010185648313 is 3138465810101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 751321436944 + 258864211369 = 866788^2 + 508787^2 .

It is a cyclic number.

It is not a de Polignac number, because 1010185648313 - 2²⁰ = 1010184599737 is a prime.

It is a super-2 number, since 2×1010185648313² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1010185648333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505092824156 + 505092824157.

It is an arithmetic number, because the mean of its divisors is an integer number (505092824157).

Almost surely, 2^{1010185648313} is an apocalyptic number.

It is an amenable number.

1010185648313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010185648313 is an equidigital number, since it uses as much as digits as its factorization.

1010185648313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 41.

The spelling of 1010185648313 in words is "one trillion, ten billion, one hundred eighty-five million, six hundred forty-eight thousand, three hundred thirteen".