Base | Representation |
---|---|
bin | 11101011001101110001… |
… | …01001110011100110011 |
3 | 10120120121110111001011011 |
4 | 32230313011032130303 |
5 | 113022433301300342 |
6 | 2052033135531351 |
7 | 132662503324321 |
oct | 16546705163463 |
9 | 3516543431134 |
10 | 1010241431347 |
11 | 35a493a50945 |
12 | 14395b989b57 |
13 | 7435acb84a5 |
14 | 36c78694d11 |
15 | 1b42a914717 |
hex | eb3714e733 |
1010241431347 has 2 divisors, whose sum is σ = 1010241431348. Its totient is φ = 1010241431346.
The previous prime is 1010241431323. The next prime is 1010241431359. The reversal of 1010241431347 is 7431341420101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1010241431347 - 27 = 1010241431219 is a prime.
It is a super-2 number, since 2×10102414313472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1010241431377) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505120715673 + 505120715674.
It is an arithmetic number, because the mean of its divisors is an integer number (505120715674).
Almost surely, 21010241431347 is an apocalyptic number.
1010241431347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010241431347 is an equidigital number, since it uses as much as digits as its factorization.
1010241431347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 1010241431347 its reverse (7431341420101), we get a palindrome (8441582851448).
The spelling of 1010241431347 in words is "one trillion, ten billion, two hundred forty-one million, four hundred thirty-one thousand, three hundred forty-seven".
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