Base | Representation |
---|---|
bin | 10010110100100000… |
… | …01101011100111001 |
3 | 222002011201011100012 |
4 | 21122100031130321 |
5 | 131143124232213 |
6 | 4350342351305 |
7 | 505250500652 |
oct | 113220153471 |
9 | 28064634305 |
10 | 10104133433 |
11 | 4315579aa9 |
12 | 1b5ba2b535 |
13 | c5044a4a4 |
14 | 6bbd0c529 |
15 | 3e20cc4a8 |
hex | 25a40d739 |
10104133433 has 2 divisors, whose sum is σ = 10104133434. Its totient is φ = 10104133432.
The previous prime is 10104133423. The next prime is 10104133453. The reversal of 10104133433 is 33433140101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7487094784 + 2617038649 = 86528^2 + 51157^2 .
It is a cyclic number.
It is not a de Polignac number, because 10104133433 - 224 = 10087356217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10104133399 and 10104133408.
It is not a weakly prime, because it can be changed into another prime (10104133423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5052066716 + 5052066717.
It is an arithmetic number, because the mean of its divisors is an integer number (5052066717).
Almost surely, 210104133433 is an apocalyptic number.
It is an amenable number.
10104133433 is a deficient number, since it is larger than the sum of its proper divisors (1).
10104133433 is an equidigital number, since it uses as much as digits as its factorization.
10104133433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 10104133433 its reverse (33433140101), we get a palindrome (43537273534).
The spelling of 10104133433 in words is "ten billion, one hundred four million, one hundred thirty-three thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •