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10104133433 is a prime number
BaseRepresentation
bin10010110100100000…
…01101011100111001
3222002011201011100012
421122100031130321
5131143124232213
64350342351305
7505250500652
oct113220153471
928064634305
1010104133433
114315579aa9
121b5ba2b535
13c5044a4a4
146bbd0c529
153e20cc4a8
hex25a40d739

10104133433 has 2 divisors, whose sum is σ = 10104133434. Its totient is φ = 10104133432.

The previous prime is 10104133423. The next prime is 10104133453. The reversal of 10104133433 is 33433140101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7487094784 + 2617038649 = 86528^2 + 51157^2 .

It is a cyclic number.

It is not a de Polignac number, because 10104133433 - 224 = 10087356217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10104133399 and 10104133408.

It is not a weakly prime, because it can be changed into another prime (10104133423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5052066716 + 5052066717.

It is an arithmetic number, because the mean of its divisors is an integer number (5052066717).

Almost surely, 210104133433 is an apocalyptic number.

It is an amenable number.

10104133433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10104133433 is an equidigital number, since it uses as much as digits as its factorization.

10104133433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 10104133433 its reverse (33433140101), we get a palindrome (43537273534).

The spelling of 10104133433 in words is "ten billion, one hundred four million, one hundred thirty-three thousand, four hundred thirty-three".