Base | Representation |
---|---|
bin | 101111000011010110… |
… | …0010001110101010100 |
3 | 100122210221010010221100 |
4 | 1132012230101311110 |
5 | 3123414231032012 |
6 | 114230255350100 |
7 | 10204651563333 |
oct | 1360654216524 |
9 | 318727103840 |
10 | 101044002132 |
11 | 39941783387 |
12 | 176bb522330 |
13 | 96b3bb4c98 |
14 | 4c67983d1a |
15 | 2965c0d8dc |
hex | 1786b11d54 |
101044002132 has 72 divisors (see below), whose sum is σ = 266578812864. Its totient is φ = 32210044416.
The previous prime is 101044002077. The next prime is 101044002133. The reversal of 101044002132 is 231200440101.
101044002132 is a `hidden beast` number, since 1 + 0 + 10 + 440 + 0 + 213 + 2 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101044002133) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5051583 + ... + 5071545.
It is an arithmetic number, because the mean of its divisors is an integer number (3702483512).
Almost surely, 2101044002132 is an apocalyptic number.
101044002132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
101044002132 is an abundant number, since it is smaller than the sum of its proper divisors (165534810732).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
101044002132 is a wasteful number, since it uses less digits than its factorization.
101044002132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26109 (or 26104 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 18.
Adding to 101044002132 its reverse (231200440101), we get a palindrome (332244442233).
The spelling of 101044002132 in words is "one hundred one billion, forty-four million, two thousand, one hundred thirty-two".
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