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101053434391 = 7132334765997
BaseRepresentation
bin101111000011101000…
…0010000101000010111
3100122211120212100120021
41132013100100220113
53123424134400031
6114231233450011
710205125006540
oct1360720205027
9318746770507
10101053434391
1139947035a38
1217702710907
1396b5b382c0
144c68d1b4c7
152966973511
hex1787410a17

101053434391 has 16 divisors (see below), whose sum is σ = 124907275584. Its totient is φ = 79611197184.

The previous prime is 101053434389. The next prime is 101053434437. The reversal of 101053434391 is 193434350101.

It is a cyclic number.

It is not a de Polignac number, because 101053434391 - 21 = 101053434389 is a prime.

It is a super-3 number, since 3×1010534343913 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101053434341) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2361796 + ... + 2404201.

It is an arithmetic number, because the mean of its divisors is an integer number (7806704724).

Almost surely, 2101053434391 is an apocalyptic number.

101053434391 is a deficient number, since it is larger than the sum of its proper divisors (23853841193).

101053434391 is a wasteful number, since it uses less digits than its factorization.

101053434391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4766250.

The product of its (nonzero) digits is 19440, while the sum is 34.

Adding to 101053434391 its reverse (193434350101), we get a palindrome (294487784492).

The spelling of 101053434391 in words is "one hundred one billion, fifty-three million, four hundred thirty-four thousand, three hundred ninety-one".

Divisors: 1 7 13 91 233 1631 3029 21203 4765997 33361979 61957961 433705727 1110477301 7773341107 14436204913 101053434391