Base | Representation |
---|---|
bin | 101111000101000000… |
… | …1111011111010001011 |
3 | 100122221211111200212022 |
4 | 1132022001323322023 |
5 | 3124023100324042 |
6 | 114240020035055 |
7 | 10206231626042 |
oct | 1361201737213 |
9 | 318854450768 |
10 | 101100011147 |
11 | 39970358823 |
12 | 17716232a8b |
13 | 96c2695505 |
14 | 4c711a3559 |
15 | 296aac3cd2 |
hex | 178a07be8b |
101100011147 has 2 divisors, whose sum is σ = 101100011148. Its totient is φ = 101100011146.
The previous prime is 101100011083. The next prime is 101100011209. The reversal of 101100011147 is 741110001101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101100011147 - 26 = 101100011083 is a prime.
It is not a weakly prime, because it can be changed into another prime (101100011647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550005573 + 50550005574.
It is an arithmetic number, because the mean of its divisors is an integer number (50550005574).
Almost surely, 2101100011147 is an apocalyptic number.
101100011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100011147 is an equidigital number, since it uses as much as digits as its factorization.
101100011147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 17.
Adding to 101100011147 its reverse (741110001101), we get a palindrome (842210012248).
The spelling of 101100011147 in words is "one hundred one billion, one hundred million, eleven thousand, one hundred forty-seven".
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