Base | Representation |
---|---|
bin | 10110111111001100101110… |
… | …010011011000000111110011 |
3 | 111020222001210122222120102001 |
4 | 112333030232103120013303 |
5 | 101222410311033341034 |
6 | 555004412045434431 |
7 | 30203143355026246 |
oct | 2677145623300763 |
9 | 436861718876361 |
10 | 101100012012019 |
11 | 2a239302121a59 |
12 | b409a3956ba17 |
13 | 44548c8568807 |
14 | 1ad73a3b2525d |
15 | ba4c9b344a14 |
hex | 5bf32e4d81f3 |
101100012012019 has 2 divisors, whose sum is σ = 101100012012020. Its totient is φ = 101100012012018.
The previous prime is 101100012012001. The next prime is 101100012012133. The reversal of 101100012012019 is 910210210001101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101100012012019 - 25 = 101100012011987 is a prime.
It is a super-2 number, since 2×1011000120120192 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 101100012011987 and 101100012012005.
It is not a weakly prime, because it can be changed into another prime (101100012012319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550006006009 + 50550006006010.
It is an arithmetic number, because the mean of its divisors is an integer number (50550006006010).
Almost surely, 2101100012012019 is an apocalyptic number.
101100012012019 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100012012019 is an equidigital number, since it uses as much as digits as its factorization.
101100012012019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 19.
The spelling of 101100012012019 in words is "one hundred one trillion, one hundred billion, twelve million, twelve thousand, nineteen".
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