Base | Representation |
---|---|
bin | 101111000101000000… |
… | …1111110110101110001 |
3 | 100122221211112022022222 |
4 | 1132022001332311301 |
5 | 3124023101220103 |
6 | 114240020210425 |
7 | 10206232006043 |
oct | 1361201766561 |
9 | 318854468288 |
10 | 101100023153 |
11 | 39970366848 |
12 | 17716239a15 |
13 | 96c269ab0c |
14 | 4c711a7a93 |
15 | 296aac7638 |
hex | 178a07ed71 |
101100023153 has 2 divisors, whose sum is σ = 101100023154. Its totient is φ = 101100023152.
The previous prime is 101100023113. The next prime is 101100023159. The reversal of 101100023153 is 351320001101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 86023130209 + 15076892944 = 293297^2 + 122788^2 .
It is a cyclic number.
It is not a de Polignac number, because 101100023153 - 212 = 101100019057 is a prime.
It is a super-2 number, since 2×1011000231532 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101100023159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550011576 + 50550011577.
It is an arithmetic number, because the mean of its divisors is an integer number (50550011577).
Almost surely, 2101100023153 is an apocalyptic number.
It is an amenable number.
101100023153 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100023153 is an equidigital number, since it uses as much as digits as its factorization.
101100023153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 101100023153 its reverse (351320001101), we get a palindrome (452420024254).
The spelling of 101100023153 in words is "one hundred one billion, one hundred million, twenty-three thousand, one hundred fifty-three".
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