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10110011099257 is a prime number
BaseRepresentation
bin1001001100011110101110…
…0111101100100001111001
31022210111201001112010112001
42103013223213230201321
52311120300320134012
633300250332421001
72062265333303146
oct223075347544171
938714631463461
1010110011099257
1132486a4775173
12117347a317761
135844a6a40424
1426d4819a13cd
15127eb7ece357
hex931eb9ec879

10110011099257 has 2 divisors, whose sum is σ = 10110011099258. Its totient is φ = 10110011099256.

The previous prime is 10110011099231. The next prime is 10110011099311. The reversal of 10110011099257 is 75299011001101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9822526396281 + 287484702976 = 3134091^2 + 536176^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10110011099257 is a prime.

It is not a weakly prime, because it can be changed into another prime (10110011099857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055005549628 + 5055005549629.

It is an arithmetic number, because the mean of its divisors is an integer number (5055005549629).

Almost surely, 210110011099257 is an apocalyptic number.

It is an amenable number.

10110011099257 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110011099257 is an equidigital number, since it uses as much as digits as its factorization.

10110011099257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5670, while the sum is 37.

The spelling of 10110011099257 in words is "ten trillion, one hundred ten billion, eleven million, ninety-nine thousand, two hundred fifty-seven".