Base | Representation |
---|---|
bin | 1001001100011110101110… |
… | …0111101100111111100001 |
3 | 1022210111201001112020010021 |
4 | 2103013223213230333201 |
5 | 2311120300320214103 |
6 | 33300250332433441 |
7 | 2062265333311525 |
oct | 223075347547741 |
9 | 38714631466107 |
10 | 10110011101153 |
11 | 32486a4776637 |
12 | 117347a318881 |
13 | 5844a6a41252 |
14 | 26d4819a1d85 |
15 | 127eb7ecebbd |
hex | 931eb9ecfe1 |
10110011101153 has 2 divisors, whose sum is σ = 10110011101154. Its totient is φ = 10110011101152.
The previous prime is 10110011101139. The next prime is 10110011101187. The reversal of 10110011101153 is 35110111001101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10051740520704 + 58270580449 = 3170448^2 + 241393^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10110011101153 is a prime.
It is not a weakly prime, because it can be changed into another prime (10110011101123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055005550576 + 5055005550577.
It is an arithmetic number, because the mean of its divisors is an integer number (5055005550577).
Almost surely, 210110011101153 is an apocalyptic number.
It is an amenable number.
10110011101153 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110011101153 is an equidigital number, since it uses as much as digits as its factorization.
10110011101153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 16.
Adding to 10110011101153 its reverse (35110111001101), we get a palindrome (45220122102254).
The spelling of 10110011101153 in words is "ten trillion, one hundred ten billion, eleven million, one hundred one thousand, one hundred fifty-three".
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