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10110011101153 is a prime number
BaseRepresentation
bin1001001100011110101110…
…0111101100111111100001
31022210111201001112020010021
42103013223213230333201
52311120300320214103
633300250332433441
72062265333311525
oct223075347547741
938714631466107
1010110011101153
1132486a4776637
12117347a318881
135844a6a41252
1426d4819a1d85
15127eb7ecebbd
hex931eb9ecfe1

10110011101153 has 2 divisors, whose sum is σ = 10110011101154. Its totient is φ = 10110011101152.

The previous prime is 10110011101139. The next prime is 10110011101187. The reversal of 10110011101153 is 35110111001101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10051740520704 + 58270580449 = 3170448^2 + 241393^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10110011101153 is a prime.

It is not a weakly prime, because it can be changed into another prime (10110011101123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055005550576 + 5055005550577.

It is an arithmetic number, because the mean of its divisors is an integer number (5055005550577).

Almost surely, 210110011101153 is an apocalyptic number.

It is an amenable number.

10110011101153 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110011101153 is an equidigital number, since it uses as much as digits as its factorization.

10110011101153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 16.

Adding to 10110011101153 its reverse (35110111001101), we get a palindrome (45220122102254).

The spelling of 10110011101153 in words is "ten trillion, one hundred ten billion, eleven million, one hundred one thousand, one hundred fifty-three".