Base | Representation |
---|---|
bin | 1001001100011110101110… |
… | …0111101111011010001011 |
3 | 1022210111201001112201200212 |
4 | 2103013223213233122023 |
5 | 2311120300321023201 |
6 | 33300250332551335 |
7 | 2062265333352425 |
oct | 223075347573213 |
9 | 38714631481625 |
10 | 10110011111051 |
11 | 32486a4783015 |
12 | 117347a32254b |
13 | 5844a6a458c7 |
14 | 26d4819a5815 |
15 | 127eb7ed2abb |
hex | 931eb9ef68b |
10110011111051 has 2 divisors, whose sum is σ = 10110011111052. Its totient is φ = 10110011111050.
The previous prime is 10110011111023. The next prime is 10110011111129. The reversal of 10110011111051 is 15011111001101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10110011111051 - 210 = 10110011110027 is a prime.
It is not a weakly prime, because it can be changed into another prime (10110011119051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055005555525 + 5055005555526.
It is an arithmetic number, because the mean of its divisors is an integer number (5055005555526).
Almost surely, 210110011111051 is an apocalyptic number.
10110011111051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110011111051 is an equidigital number, since it uses as much as digits as its factorization.
10110011111051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5, while the sum is 14.
Adding to 10110011111051 its reverse (15011111001101), we get a palindrome (25121122112152).
The spelling of 10110011111051 in words is "ten trillion, one hundred ten billion, eleven million, one hundred eleven thousand, fifty-one".
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