1011001212019 has 2 divisors, whose sum is σ = 1011001212020. Its totient is φ = 1011001212018.

The previous prime is 1011001212007. The next prime is 1011001212047. The reversal of 1011001212019 is 9102121001101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1011001212019 - 2³⁵ = 976641473651 is a prime.

It is a super-2 number, since 2×1011001212019² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011001211987 and 1011001212005.

It is not a weakly prime, because it can be changed into another prime (1011001282019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505500606009 + 505500606010.

It is an arithmetic number, because the mean of its divisors is an integer number (505500606010).

Almost surely, 2^{1011001212019} is an apocalyptic number.

1011001212019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011001212019 is an equidigital number, since it uses as much as digits as its factorization.

1011001212019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 19.

The spelling of 1011001212019 in words is "one trillion, eleven billion, one million, two hundred twelve thousand, nineteen".