Search a number
-
+
10110020121011 is a prime number
BaseRepresentation
bin1001001100011110110000…
…1010000111000110110011
31022210111201200111111001002
42103013230022013012303
52311120310122333021
633300251254032215
72062265503056506
oct223075412070663
938714650444032
1010110020121011
1132486a9877368
12117348134866b
135844a887b945
1426d482c6d13d
15127eb8bb250b
hex931ec2871b3

10110020121011 has 2 divisors, whose sum is σ = 10110020121012. Its totient is φ = 10110020121010.

The previous prime is 10110020120987. The next prime is 10110020121023. The reversal of 10110020121011 is 11012102001101.

It is a strong prime.

It is an emirp because it is prime and its reverse (11012102001101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10110020121011 - 218 = 10110019858867 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10110020120983 and 10110020121001.

It is not a weakly prime, because it can be changed into another prime (10110022121011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055010060505 + 5055010060506.

It is an arithmetic number, because the mean of its divisors is an integer number (5055010060506).

Almost surely, 210110020121011 is an apocalyptic number.

10110020121011 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110020121011 is an equidigital number, since it uses as much as digits as its factorization.

10110020121011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 10110020121011 its reverse (11012102001101), we get a palindrome (21122122122112).

The spelling of 10110020121011 in words is "ten trillion, one hundred ten billion, twenty million, one hundred twenty-one thousand, eleven".