Base | Representation |
---|---|
bin | 1001001100011110110000… |
… | …1010000111000110110011 |
3 | 1022210111201200111111001002 |
4 | 2103013230022013012303 |
5 | 2311120310122333021 |
6 | 33300251254032215 |
7 | 2062265503056506 |
oct | 223075412070663 |
9 | 38714650444032 |
10 | 10110020121011 |
11 | 32486a9877368 |
12 | 117348134866b |
13 | 5844a887b945 |
14 | 26d482c6d13d |
15 | 127eb8bb250b |
hex | 931ec2871b3 |
10110020121011 has 2 divisors, whose sum is σ = 10110020121012. Its totient is φ = 10110020121010.
The previous prime is 10110020120987. The next prime is 10110020121023. The reversal of 10110020121011 is 11012102001101.
It is a strong prime.
It is an emirp because it is prime and its reverse (11012102001101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10110020121011 - 218 = 10110019858867 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10110020120983 and 10110020121001.
It is not a weakly prime, because it can be changed into another prime (10110022121011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055010060505 + 5055010060506.
It is an arithmetic number, because the mean of its divisors is an integer number (5055010060506).
Almost surely, 210110020121011 is an apocalyptic number.
10110020121011 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110020121011 is an equidigital number, since it uses as much as digits as its factorization.
10110020121011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 10110020121011 its reverse (11012102001101), we get a palindrome (21122122122112).
The spelling of 10110020121011 in words is "ten trillion, one hundred ten billion, twenty million, one hundred twenty-one thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •