Base | Representation |
---|---|
bin | 11101011011001000110… |
… | …11011000001011110011 |
3 | 10120122120111000202112101 |
4 | 32231210123120023303 |
5 | 113031013031304412 |
6 | 2052240434041231 |
7 | 133020402010045 |
oct | 16554433301363 |
9 | 3518514022471 |
10 | 1011002213107 |
11 | 35a8444354a7 |
12 | 143b32719217 |
13 | 7444c7b9603 |
14 | 36d0b731a95 |
15 | 1b4725e1457 |
hex | eb646d82f3 |
1011002213107 has 2 divisors, whose sum is σ = 1011002213108. Its totient is φ = 1011002213106.
The previous prime is 1011002213087. The next prime is 1011002213147. The reversal of 1011002213107 is 7013122001101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1011002213107 - 223 = 1010993824499 is a prime.
It is a super-4 number, since 4×10110022131074 (a number of 49 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (1011002213147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505501106553 + 505501106554.
It is an arithmetic number, because the mean of its divisors is an integer number (505501106554).
Almost surely, 21011002213107 is an apocalyptic number.
1011002213107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011002213107 is an equidigital number, since it uses as much as digits as its factorization.
1011002213107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 1011002213107 its reverse (7013122001101), we get a palindrome (8024124214208).
The spelling of 1011002213107 in words is "one trillion, eleven billion, two million, two hundred thirteen thousand, one hundred seven".
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