Base | Representation |
---|---|
bin | 10110111111001100111010… |
… | …111000101111010111001011 |
3 | 111020222002100101020122010111 |
4 | 112333030322320233113023 |
5 | 101222411224110230011 |
6 | 555004445030455151 |
7 | 30203151530362555 |
oct | 2677147270572713 |
9 | 436862311218114 |
10 | 101100223133131 |
11 | 2a239400310412 |
12 | b409a982044b7 |
13 | 4454930217a51 |
14 | 1ad73c3ba04d5 |
15 | ba4caeb49121 |
hex | 5bf33ae2f5cb |
101100223133131 has 2 divisors, whose sum is σ = 101100223133132. Its totient is φ = 101100223133130.
The previous prime is 101100223133099. The next prime is 101100223133141. The reversal of 101100223133131 is 131331322001101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101100223133131 - 25 = 101100223133099 is a prime.
It is a super-2 number, since 2×1011002231331312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101100223133141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550111566565 + 50550111566566.
It is an arithmetic number, because the mean of its divisors is an integer number (50550111566566).
Almost surely, 2101100223133131 is an apocalyptic number.
101100223133131 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100223133131 is an equidigital number, since it uses as much as digits as its factorization.
101100223133131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 101100223133131 its reverse (131331322001101), we get a palindrome (232431545134232).
The spelling of 101100223133131 in words is "one hundred one trillion, one hundred billion, two hundred twenty-three million, one hundred thirty-three thousand, one hundred thirty-one".
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