Base | Representation |
---|---|
bin | 11101011011001000111… |
… | …10110001010001101001 |
3 | 10120122120112200221021221 |
4 | 32231210132301101221 |
5 | 113031013243233223 |
6 | 2052240505102041 |
7 | 133020412402351 |
oct | 16554436612151 |
9 | 3518515627257 |
10 | 1011003102313 |
11 | 35a844992586 |
12 | 143b32a87921 |
13 | 7444ca3b279 |
14 | 36d0b8c3b61 |
15 | 1b472719b5d |
hex | eb647b1469 |
1011003102313 has 2 divisors, whose sum is σ = 1011003102314. Its totient is φ = 1011003102312.
The previous prime is 1011003102301. The next prime is 1011003102337. The reversal of 1011003102313 is 3132013001101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 627728197849 + 383274904464 = 792293^2 + 619092^2 .
It is a cyclic number.
It is not a de Polignac number, because 1011003102313 - 25 = 1011003102281 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011003102353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505501551156 + 505501551157.
It is an arithmetic number, because the mean of its divisors is an integer number (505501551157).
Almost surely, 21011003102313 is an apocalyptic number.
It is an amenable number.
1011003102313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011003102313 is an equidigital number, since it uses as much as digits as its factorization.
1011003102313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1011003102313 its reverse (3132013001101), we get a palindrome (4143016103414).
The spelling of 1011003102313 in words is "one trillion, eleven billion, three million, one hundred two thousand, three hundred thirteen".
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