Search a number
-
+
10110031213212 = 22327286491400369
BaseRepresentation
bin1001001100011110110011…
…0100011011001010011100
31022210111202110101000200100
42103013230310123022130
52311120320442310322
633300252331501100
72062265666255340
oct223075464331234
938714673330610
1010110031213212
113248705063077
121173484bb7790
135844aac63688
1426d484519620
15127eb9b53dac
hex931ecd1b29c

10110031213212 has 72 divisors (see below), whose sum is σ = 29207797164000. Its totient is φ = 2888477457408.

The previous prime is 10110031213211. The next prime is 10110031213253. The reversal of 10110031213212 is 21231213001101.

10110031213212 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×101100312132122 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10110031213211) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6519364 + ... + 7919732.

It is an arithmetic number, because the mean of its divisors is an integer number (405663849500).

Almost surely, 210110031213212 is an apocalyptic number.

10110031213212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

10110031213212 is an abundant number, since it is smaller than the sum of its proper divisors (19097765950788).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10110031213212 is a wasteful number, since it uses less digits than its factorization.

10110031213212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1429035 (or 1429030 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 10110031213212 its reverse (21231213001101), we get a palindrome (31341244214313).

The spelling of 10110031213212 in words is "ten trillion, one hundred ten billion, thirty-one million, two hundred thirteen thousand, two hundred twelve".

Divisors: 1 2 3 4 6 7 9 12 14 18 21 28 36 42 63 84 126 252 28649 57298 85947 114596 171894 200543 257841 343788 401086 515682 601629 802172 1031364 1203258 1400369 1804887 2406516 2800738 3609774 4201107 5601476 7219548 8402214 9802583 12603321 16804428 19605166 25206642 29407749 39210332 50413284 58815498 88223247 117630996 176446494 352892988 40119171481 80238342962 120357514443 160476685924 240715028886 280834200367 361072543329 481430057772 561668400734 722145086658 842502601101 1123336801468 1444290173316 1685005202202 2527507803303 3370010404404 5055015606606 10110031213212