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10110034111 = 51711955141
BaseRepresentation
bin10010110101001101…
…01110000010111111
3222002120210221112211
421122212232002333
5131201132042421
64351113041251
7505351605052
oct113246560277
928076727484
1010110034111
11431893a2a1
121b619b6227
13c51735208
146bca06a99
153e28959e1
hex25a9ae0bf

10110034111 has 4 divisors (see below), whose sum is σ = 10111994424. Its totient is φ = 10108073800.

The previous prime is 10110034073. The next prime is 10110034117. The reversal of 10110034111 is 11143001101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10110034111 - 211 = 10110032063 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10110034091 and 10110034100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10110034117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 972400 + ... + 982741.

It is an arithmetic number, because the mean of its divisors is an integer number (2527998606).

Almost surely, 210110034111 is an apocalyptic number.

10110034111 is a deficient number, since it is larger than the sum of its proper divisors (1960313).

10110034111 is an equidigital number, since it uses as much as digits as its factorization.

10110034111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1960312.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10110034111 its reverse (11143001101), we get a palindrome (21253035212).

The spelling of 10110034111 in words is "ten billion, one hundred ten million, thirty-four thousand, one hundred eleven".

Divisors: 1 5171 1955141 10110034111