Base | Representation |
---|---|
bin | 101111000101000011… |
… | …0000101110001111001 |
3 | 100122221220120000200212 |
4 | 1132022012011301321 |
5 | 3124023340201103 |
6 | 114240055240505 |
7 | 10206244113014 |
oct | 1361206056171 |
9 | 318856500625 |
10 | 101101100153 |
11 | 39970a31a29 |
12 | 17716679135 |
13 | 96c29870b1 |
14 | 4c713a837b |
15 | 296ac3b7d8 |
hex | 178a185c79 |
101101100153 has 2 divisors, whose sum is σ = 101101100154. Its totient is φ = 101101100152.
The previous prime is 101101100083. The next prime is 101101100183. The reversal of 101101100153 is 351001101101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76152265849 + 24948834304 = 275957^2 + 157952^2 .
It is a cyclic number.
It is not a de Polignac number, because 101101100153 - 210 = 101101099129 is a prime.
It is not a weakly prime, because it can be changed into another prime (101101100183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550550076 + 50550550077.
It is an arithmetic number, because the mean of its divisors is an integer number (50550550077).
Almost surely, 2101101100153 is an apocalyptic number.
It is an amenable number.
101101100153 is a deficient number, since it is larger than the sum of its proper divisors (1).
101101100153 is an equidigital number, since it uses as much as digits as its factorization.
101101100153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 14.
Adding to 101101100153 its reverse (351001101101), we get a palindrome (452102201254).
The spelling of 101101100153 in words is "one hundred one billion, one hundred one million, one hundred thousand, one hundred fifty-three".
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