101102121000113 has 2 divisors, whose sum is σ = 101102121000114. Its totient is φ = 101102121000112.

The previous prime is 101102121000091. The next prime is 101102121000119. The reversal of 101102121000113 is 311000121201101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100666868090944 + 435252909169 = 10033288^2 + 659737^2 .

It is a cyclic number.

It is not a de Polignac number, because 101102121000113 - 2²⁴ = 101102104222897 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (101102121000119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551060500056 + 50551060500057.

It is an arithmetic number, because the mean of its divisors is an integer number (50551060500057).

Almost surely, 2^{101102121000113} is an apocalyptic number.

It is an amenable number.

101102121000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101102121000113 is an equidigital number, since it uses as much as digits as its factorization.

101102121000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 101102121000113 its reverse (311000121201101), we get a palindrome (412102242201214).

The spelling of 101102121000113 in words is "one hundred one trillion, one hundred two billion, one hundred twenty-one million, one hundred thirteen", and thus it is an aban number.