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1011021320203 is a prime number
BaseRepresentation
bin11101011011001011001…
…00010001000000001011
310120122121210222111112121
432231211210101000023
5113031032424221303
62052242355352111
7133021023266626
oct16554544210013
93518553874477
101011021320203
1135a8541a5994
12143b38bb2637
137445374949b
1436d100a6dbd
151b4741179bd
hexeb6591100b

1011021320203 has 2 divisors, whose sum is σ = 1011021320204. Its totient is φ = 1011021320202.

The previous prime is 1011021320173. The next prime is 1011021320209. The reversal of 1011021320203 is 3020231201101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1011021320203 is a prime.

It is a super-2 number, since 2×10110213202032 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011021320209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505510660101 + 505510660102.

It is an arithmetic number, because the mean of its divisors is an integer number (505510660102).

Almost surely, 21011021320203 is an apocalyptic number.

1011021320203 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011021320203 is an equidigital number, since it uses as much as digits as its factorization.

1011021320203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1011021320203 its reverse (3020231201101), we get a palindrome (4031252521304).

The spelling of 1011021320203 in words is "one trillion, eleven billion, twenty-one million, three hundred twenty thousand, two hundred three".