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101102199880147 is a prime number
BaseRepresentation
bin10110111111001110110000…
…101101011011100111010011
3111020222021110010211210020221
4112333032300231123213103
5101222424301132131042
6555005413123213511
730203251522426444
oct2677166055334723
9436867403753227
10101102199880147
112a23a225115734
12b40a34a217297
134454b8691013b
141ad75305252cb
15ba4d78466d67
hex5bf3b0b5b9d3

101102199880147 has 2 divisors, whose sum is σ = 101102199880148. Its totient is φ = 101102199880146.

The previous prime is 101102199880111. The next prime is 101102199880169. The reversal of 101102199880147 is 741088991201101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101102199880147 - 227 = 101102065662419 is a prime.

It is a super-2 number, since 2×1011021998801472 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101102199880094 and 101102199880103.

It is not a weakly prime, because it can be changed into another prime (101102199880177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551099940073 + 50551099940074.

It is an arithmetic number, because the mean of its divisors is an integer number (50551099940074).

Almost surely, 2101102199880147 is an apocalyptic number.

101102199880147 is a deficient number, since it is larger than the sum of its proper divisors (1).

101102199880147 is an equidigital number, since it uses as much as digits as its factorization.

101102199880147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 290304, while the sum is 52.

The spelling of 101102199880147 in words is "one hundred one trillion, one hundred two billion, one hundred ninety-nine million, eight hundred eighty thousand, one hundred forty-seven".