Base | Representation |
---|---|
bin | 10110111111001110110000… |
… | …110010011110010110100011 |
3 | 111020222021110020022221121112 |
4 | 112333032300302132112203 |
5 | 101222424302001431313 |
6 | 555005413211413535 |
7 | 30203251536603464 |
oct | 2677166062362643 |
9 | 436867406287545 |
10 | 101102201202083 |
11 | 2a23a225938944 |
12 | b40a34a7542ab |
13 | 4454b86c83a53 |
14 | 1ad753078ad6b |
15 | ba4d786288a8 |
hex | 5bf3b0c9e5a3 |
101102201202083 has 2 divisors, whose sum is σ = 101102201202084. Its totient is φ = 101102201202082.
The previous prime is 101102201202071. The next prime is 101102201202091. The reversal of 101102201202083 is 380202102201101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101102201202083 - 224 = 101102184424867 is a prime.
It is a super-4 number, since 4×1011022012020834 (a number of 57 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (101102201202283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551100601041 + 50551100601042.
It is an arithmetic number, because the mean of its divisors is an integer number (50551100601042).
Almost surely, 2101102201202083 is an apocalyptic number.
101102201202083 is a deficient number, since it is larger than the sum of its proper divisors (1).
101102201202083 is an equidigital number, since it uses as much as digits as its factorization.
101102201202083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 101102201202083 its reverse (380202102201101), we get a palindrome (481304303403184).
The spelling of 101102201202083 in words is "one hundred one trillion, one hundred two billion, two hundred one million, two hundred two thousand, eighty-three".
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