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101102201202083 is a prime number
BaseRepresentation
bin10110111111001110110000…
…110010011110010110100011
3111020222021110020022221121112
4112333032300302132112203
5101222424302001431313
6555005413211413535
730203251536603464
oct2677166062362643
9436867406287545
10101102201202083
112a23a225938944
12b40a34a7542ab
134454b86c83a53
141ad753078ad6b
15ba4d786288a8
hex5bf3b0c9e5a3

101102201202083 has 2 divisors, whose sum is σ = 101102201202084. Its totient is φ = 101102201202082.

The previous prime is 101102201202071. The next prime is 101102201202091. The reversal of 101102201202083 is 380202102201101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101102201202083 - 224 = 101102184424867 is a prime.

It is a super-4 number, since 4×1011022012020834 (a number of 57 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (101102201202283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551100601041 + 50551100601042.

It is an arithmetic number, because the mean of its divisors is an integer number (50551100601042).

Almost surely, 2101102201202083 is an apocalyptic number.

101102201202083 is a deficient number, since it is larger than the sum of its proper divisors (1).

101102201202083 is an equidigital number, since it uses as much as digits as its factorization.

101102201202083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 101102201202083 its reverse (380202102201101), we get a palindrome (481304303403184).

The spelling of 101102201202083 in words is "one hundred one trillion, one hundred two billion, two hundred one million, two hundred two thousand, eighty-three".