Base | Representation |
---|---|
bin | 10110111111001110110000… |
… | …110010100000110001111011 |
3 | 111020222021110020100110020211 |
4 | 112333032300302200301323 |
5 | 101222424302002241102 |
6 | 555005413211531551 |
7 | 30203251536644461 |
oct | 2677166062406173 |
9 | 436867406313224 |
10 | 101102201212027 |
11 | 2a23a225945364 |
12 | b40a34a759bb7 |
13 | 4454b86c88432 |
14 | 1ad7530790831 |
15 | ba4d7862b7d7 |
hex | 5bf3b0ca0c7b |
101102201212027 has 2 divisors, whose sum is σ = 101102201212028. Its totient is φ = 101102201212026.
The previous prime is 101102201211961. The next prime is 101102201212037. The reversal of 101102201212027 is 720212102201101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101102201212027 - 211 = 101102201209979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101102201211989 and 101102201212007.
It is not a weakly prime, because it can be changed into another prime (101102201212037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551100606013 + 50551100606014.
It is an arithmetic number, because the mean of its divisors is an integer number (50551100606014).
Almost surely, 2101102201212027 is an apocalyptic number.
101102201212027 is a deficient number, since it is larger than the sum of its proper divisors (1).
101102201212027 is an equidigital number, since it uses as much as digits as its factorization.
101102201212027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 101102201212027 its reverse (720212102201101), we get a palindrome (821314303413128).
The spelling of 101102201212027 in words is "one hundred one trillion, one hundred two billion, two hundred one million, two hundred twelve thousand, twenty-seven".
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