Base | Representation |
---|---|
bin | 10010110101001111… |
… | …01111100100100001 |
3 | 222002121022120201001 |
4 | 21122213233210201 |
5 | 131201214134442 |
6 | 4351122512001 |
7 | 505354103401 |
oct | 113247574441 |
9 | 28077276631 |
10 | 10110302497 |
11 | 43190029a9 |
12 | 1b61b05601 |
13 | c517ca419 |
14 | 6bca76801 |
15 | 3e28ea2b7 |
hex | 25a9ef921 |
10110302497 has 2 divisors, whose sum is σ = 10110302498. Its totient is φ = 10110302496.
The previous prime is 10110302387. The next prime is 10110302539. The reversal of 10110302497 is 79420301101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9101350801 + 1008951696 = 95401^2 + 31764^2 .
It is an emirp because it is prime and its reverse (79420301101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10110302497 - 231 = 7962818849 is a prime.
It is not a weakly prime, because it can be changed into another prime (10110302197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055151248 + 5055151249.
It is an arithmetic number, because the mean of its divisors is an integer number (5055151249).
Almost surely, 210110302497 is an apocalyptic number.
It is an amenable number.
10110302497 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110302497 is an equidigital number, since it uses as much as digits as its factorization.
10110302497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 10110302497 its reverse (79420301101), we get a palindrome (89530603598).
The spelling of 10110302497 in words is "ten billion, one hundred ten million, three hundred two thousand, four hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •