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101103113330 = 2520175012549
BaseRepresentation
bin101111000101000110…
…1110001010001110010
3100122222001100022020222
41132022031301101302
53124024344111310
6114240210333042
710206300166232
oct1361215612162
9318861308228
10101103113330
113997208750a
121771728a182
1396c321051b
144c7176dcc2
15296aed8055
hex178a371472

101103113330 has 16 divisors (see below), whose sum is σ = 182075866200. Its totient is φ = 40421187072.

The previous prime is 101103113327. The next prime is 101103113341. The reversal of 101103113330 is 33311301101.

It can be written as a sum of positive squares in 4 ways, for example, as 101075033929 + 28079401 = 317923^2 + 5299^2 .

It is a junction number, because it is equal to n+sod(n) for n = 101103113299 and 101103113308.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2486105 + ... + 2526444.

Almost surely, 2101103113330 is an apocalyptic number.

101103113330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

101103113330 is a deficient number, since it is larger than the sum of its proper divisors (80972752870).

101103113330 is a wasteful number, since it uses less digits than its factorization.

101103113330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5014573.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 101103113330 its reverse (33311301101), we get a palindrome (134414414431).

The spelling of 101103113330 in words is "one hundred one billion, one hundred three million, one hundred thirteen thousand, three hundred thirty".

Divisors: 1 2 5 10 2017 4034 10085 20170 5012549 10025098 25062745 50125490 10110311333 20220622666 50551556665 101103113330