Base | Representation |
---|---|
bin | 10110111111001111100111… |
… | …101100001110100000100001 |
3 | 111020222100211102120010210001 |
4 | 112333033213230032200201 |
5 | 101222433143302424301 |
6 | 555010044434140001 |
7 | 30203313423111013 |
oct | 2677174754164041 |
9 | 436870742503701 |
10 | 101103122311201 |
11 | 2a23a65887884a |
12 | b40a567121601 |
13 | 4454ca2a5b62a |
14 | 1ad75bac401b3 |
15 | ba4dce424c01 |
hex | 5bf3e7b0e821 |
101103122311201 has 2 divisors, whose sum is σ = 101103122311202. Its totient is φ = 101103122311200.
The previous prime is 101103122311141. The next prime is 101103122311313. The reversal of 101103122311201 is 102113221301101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 81056727928801 + 20046394382400 = 9003151^2 + 4477320^2 .
It is a cyclic number.
It is not a de Polignac number, because 101103122311201 - 227 = 101102988093473 is a prime.
It is not a weakly prime, because it can be changed into another prime (101103122411201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551561155600 + 50551561155601.
It is an arithmetic number, because the mean of its divisors is an integer number (50551561155601).
Almost surely, 2101103122311201 is an apocalyptic number.
It is an amenable number.
101103122311201 is a deficient number, since it is larger than the sum of its proper divisors (1).
101103122311201 is an equidigital number, since it uses as much as digits as its factorization.
101103122311201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 101103122311201 its reverse (102113221301101), we get a palindrome (203216343612302).
The spelling of 101103122311201 in words is "one hundred one trillion, one hundred three billion, one hundred twenty-two million, three hundred eleven thousand, two hundred one".
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