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10110320221 = 83121811087
BaseRepresentation
bin10010110101001111…
…10011111001011101
3222002121100111000111
421122213303321131
5131201220221341
64351123130021
7505354206151
oct113247637135
928077314014
1010110320221
114319015251
121b61b13911
13c51805501
146bca7d061
153e2900681
hex25a9f3e5d

10110320221 has 4 divisors (see below), whose sum is σ = 10232131392. Its totient is φ = 9988509052.

The previous prime is 10110320219. The next prime is 10110320237. The reversal of 10110320221 is 12202301101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10110320221 - 21 = 10110320219 is a prime.

It is a super-2 number, since 2×101103202212 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10110323221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60905461 + ... + 60905626.

It is an arithmetic number, because the mean of its divisors is an integer number (2558032848).

Almost surely, 210110320221 is an apocalyptic number.

It is an amenable number.

10110320221 is a deficient number, since it is larger than the sum of its proper divisors (121811171).

10110320221 is an equidigital number, since it uses as much as digits as its factorization.

10110320221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121811170.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10110320221 its reverse (12202301101), we get a palindrome (22312621322).

The spelling of 10110320221 in words is "ten billion, one hundred ten million, three hundred twenty thousand, two hundred twenty-one".

Divisors: 1 83 121811087 10110320221