101110011001411 has 2 divisors, whose sum is σ = 101110011001412. Its totient is φ = 101110011001410.

The previous prime is 101110011001333. The next prime is 101110011001421. The reversal of 101110011001411 is 114100110011101.

It is a strong prime.

It is an emirp because it is prime and its reverse (114100110011101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101110011001411 - 2¹⁹ = 101110010477123 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101110011001391 and 101110011001400.

It is not a weakly prime, because it can be changed into another prime (101110011001421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555005500705 + 50555005500706.

It is an arithmetic number, because the mean of its divisors is an integer number (50555005500706).

Almost surely, 2^{101110011001411} is an apocalyptic number.

101110011001411 is a deficient number, since it is larger than the sum of its proper divisors (1).

101110011001411 is an equidigital number, since it uses as much as digits as its factorization.

101110011001411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 101110011001411 its reverse (114100110011101), we get a palindrome (215210121012512).

The spelling of 101110011001411 in words is "one hundred one trillion, one hundred ten billion, eleven million, one thousand, four hundred eleven".