Base | Representation |
---|---|
bin | 11101011011010100110… |
… | …00110110001110110001 |
3 | 10120122211110012021122122 |
4 | 32231222120312032301 |
5 | 113031214131304131 |
6 | 2052254405244025 |
7 | 133023025002044 |
oct | 16555230661661 |
9 | 3518743167578 |
10 | 1011102213041 |
11 | 35a895926978 |
12 | 143b60103615 |
13 | 7446743007b |
14 | 36d1ab22c5b |
15 | 1b47b295d7b |
hex | eb6a6363b1 |
1011102213041 has 2 divisors, whose sum is σ = 1011102213042. Its totient is φ = 1011102213040.
The previous prime is 1011102213019. The next prime is 1011102213061. The reversal of 1011102213041 is 1403122011101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1010618037025 + 484176016 = 1005295^2 + 22004^2 .
It is a cyclic number.
It is not a de Polignac number, because 1011102213041 - 26 = 1011102212977 is a prime.
It is a super-3 number, since 3×10111022130413 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1011102213061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505551106520 + 505551106521.
It is an arithmetic number, because the mean of its divisors is an integer number (505551106521).
Almost surely, 21011102213041 is an apocalyptic number.
It is an amenable number.
1011102213041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011102213041 is an equidigital number, since it uses as much as digits as its factorization.
1011102213041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1011102213041 its reverse (1403122011101), we get a palindrome (2414224224142).
The spelling of 1011102213041 in words is "one trillion, eleven billion, one hundred two million, two hundred thirteen thousand, forty-one".
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