10111099931 has 2 divisors, whose sum is σ = 10111099932. Its totient is φ = 10111099930.

The previous prime is 10111099883. The next prime is 10111099949. The reversal of 10111099931 is 13999011101.

It is a strong prime.

It is an emirp because it is prime and its reverse (13999011101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10111099931 - 2¹⁴ = 10111083547 is a prime.

It is a super-2 number, since 2×10111099931² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10111099891 and 10111099900.

It is not a weakly prime, because it can be changed into another prime (10111099981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055549965 + 5055549966.

It is an arithmetic number, because the mean of its divisors is an integer number (5055549966).

Almost surely, 2^10111099931 is an apocalyptic number.

10111099931 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111099931 is an equidigital number, since it uses as much as digits as its factorization.

10111099931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2187, while the sum is 35.

The spelling of 10111099931 in words is "ten billion, one hundred eleven million, ninety-nine thousand, nine hundred thirty-one".