101111011122113 has 2 divisors, whose sum is σ = 101111011122114. Its totient is φ = 101111011122112.

The previous prime is 101111011122089. The next prime is 101111011122127. The reversal of 101111011122113 is 311221110111101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59668471864369 + 41442539257744 = 7724537^2 + 6437588^2 .

It is an emirp because it is prime and its reverse (311221110111101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101111011122113 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101111011122091 and 101111011122100.

It is not a weakly prime, because it can be changed into another prime (101111014122113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555505561056 + 50555505561057.

It is an arithmetic number, because the mean of its divisors is an integer number (50555505561057).

Almost surely, 2^{101111011122113} is an apocalyptic number.

It is an amenable number.

101111011122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101111011122113 is an equidigital number, since it uses as much as digits as its factorization.

101111011122113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 17.

Adding to 101111011122113 its reverse (311221110111101), we get a palindrome (412332121233214).

The spelling of 101111011122113 in words is "one hundred one trillion, one hundred eleven billion, eleven million, one hundred twenty-two thousand, one hundred thirteen".