Base | Representation |
---|---|
bin | 11101011011010110111… |
… | …00101100110001000011 |
3 | 10120122212200122221212101 |
4 | 32231223130230301003 |
5 | 113031233210000232 |
6 | 2052300242411231 |
7 | 133023332123212 |
oct | 16555334546103 |
9 | 3518780587771 |
10 | 1011120000067 |
11 | 35a8a49755a1 |
12 | 143b66060b17 |
13 | 7446b01a138 |
14 | 36d1d233079 |
15 | 1b47cb0b1e7 |
hex | eb6b72cc43 |
1011120000067 has 2 divisors, whose sum is σ = 1011120000068. Its totient is φ = 1011120000066.
The previous prime is 1011120000047. The next prime is 1011120000113. The reversal of 1011120000067 is 7600000211101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1011120000067 - 235 = 976760261699 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1011119999999 and 1011120000053.
It is not a weakly prime, because it can be changed into another prime (1011120000047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505560000033 + 505560000034.
It is an arithmetic number, because the mean of its divisors is an integer number (505560000034).
Almost surely, 21011120000067 is an apocalyptic number.
1011120000067 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011120000067 is an equidigital number, since it uses as much as digits as its factorization.
1011120000067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 1011120000067 its reverse (7600000211101), we get a palindrome (8611120211168).
The spelling of 1011120000067 in words is "one trillion, eleven billion, one hundred twenty million, sixty-seven", and thus it is an aban number.
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