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1011120212017 is a prime number
BaseRepresentation
bin11101011011010110111…
…01100000100000110001
310120122212201001201121101
432231223131200200301
5113031233233241032
62052300251124401
7133023333665146
oct16555335404061
93518781051541
101011120212017
1135a8a4aaa863
12143b66143701
137446b092756
1436d1d28a3cd
151b47cb4dde7
hexeb6b760831

1011120212017 has 2 divisors, whose sum is σ = 1011120212018. Its totient is φ = 1011120212016.

The previous prime is 1011120211999. The next prime is 1011120212029. The reversal of 1011120212017 is 7102120211101.

1011120212017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 999568046656 + 11552165361 = 999784^2 + 107481^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1011120212017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011120211985 and 1011120212003.

It is not a weakly prime, because it can be changed into another prime (1011120212087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505560106008 + 505560106009.

It is an arithmetic number, because the mean of its divisors is an integer number (505560106009).

Almost surely, 21011120212017 is an apocalyptic number.

It is an amenable number.

1011120212017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011120212017 is an equidigital number, since it uses as much as digits as its factorization.

1011120212017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 1011120212017 its reverse (7102120211101), we get a palindrome (8113240423118).

The spelling of 1011120212017 in words is "one trillion, eleven billion, one hundred twenty million, two hundred twelve thousand, seventeen".