Base | Representation |
---|---|
bin | 10110111111010111111111… |
… | …011101010110101010000001 |
3 | 111021000020000212100212000011 |
4 | 112333113333131112222001 |
5 | 101223110100404001233 |
6 | 555014132413024521 |
7 | 30204052240522246 |
oct | 2677277735265201 |
9 | 437006025325004 |
10 | 101112111000193 |
11 | 2a243450743937 |
12 | b410255485141 |
13 | 4455aa607b407 |
14 | 1ad7bd094d5cd |
15 | ba525861a0cd |
hex | 5bf5ff756a81 |
101112111000193 has 2 divisors, whose sum is σ = 101112111000194. Its totient is φ = 101112111000192.
The previous prime is 101112111000181. The next prime is 101112111000239. The reversal of 101112111000193 is 391000111211101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100956837961984 + 155273038209 = 10047728^2 + 394047^2 .
It is a cyclic number.
It is not a de Polignac number, because 101112111000193 - 25 = 101112111000161 is a prime.
It is not a weakly prime, because it can be changed into another prime (101112111000793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556055500096 + 50556055500097.
It is an arithmetic number, because the mean of its divisors is an integer number (50556055500097).
Almost surely, 2101112111000193 is an apocalyptic number.
It is an amenable number.
101112111000193 is a deficient number, since it is larger than the sum of its proper divisors (1).
101112111000193 is an equidigital number, since it uses as much as digits as its factorization.
101112111000193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 22.
Adding to 101112111000193 its reverse (391000111211101), we get a palindrome (492112222211294).
The spelling of 101112111000193 in words is "one hundred one trillion, one hundred twelve billion, one hundred eleven million, one hundred ninety-three", and thus it is an aban number.
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