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101112111000193 is a prime number
BaseRepresentation
bin10110111111010111111111…
…011101010110101010000001
3111021000020000212100212000011
4112333113333131112222001
5101223110100404001233
6555014132413024521
730204052240522246
oct2677277735265201
9437006025325004
10101112111000193
112a243450743937
12b410255485141
134455aa607b407
141ad7bd094d5cd
15ba525861a0cd
hex5bf5ff756a81

101112111000193 has 2 divisors, whose sum is σ = 101112111000194. Its totient is φ = 101112111000192.

The previous prime is 101112111000181. The next prime is 101112111000239. The reversal of 101112111000193 is 391000111211101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100956837961984 + 155273038209 = 10047728^2 + 394047^2 .

It is a cyclic number.

It is not a de Polignac number, because 101112111000193 - 25 = 101112111000161 is a prime.

It is not a weakly prime, because it can be changed into another prime (101112111000793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556055500096 + 50556055500097.

It is an arithmetic number, because the mean of its divisors is an integer number (50556055500097).

Almost surely, 2101112111000193 is an apocalyptic number.

It is an amenable number.

101112111000193 is a deficient number, since it is larger than the sum of its proper divisors (1).

101112111000193 is an equidigital number, since it uses as much as digits as its factorization.

101112111000193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 22.

Adding to 101112111000193 its reverse (391000111211101), we get a palindrome (492112222211294).

The spelling of 101112111000193 in words is "one hundred one trillion, one hundred twelve billion, one hundred eleven million, one hundred ninety-three", and thus it is an aban number.