Base | Representation |
---|---|
bin | 1001001100100011001100… |
… | …1100110001011010110011 |
3 | 1022210121210202020020221102 |
4 | 2103020303030301122303 |
5 | 2311130230233012242 |
6 | 33301005432115015 |
7 | 2062340154635231 |
oct | 223106314613263 |
9 | 38717722206842 |
10 | 10111212000947 |
11 | 3249160637402 |
12 | 1173754535a6b |
13 | 58463878c145 |
14 | 26d557287951 |
15 | 128038646e32 |
hex | 932333316b3 |
10111212000947 has 2 divisors, whose sum is σ = 10111212000948. Its totient is φ = 10111212000946.
The previous prime is 10111212000917. The next prime is 10111212001019. The reversal of 10111212000947 is 74900021211101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10111212000947 - 214 = 10111211984563 is a prime.
It is not a weakly prime, because it can be changed into another prime (10111212000917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055606000473 + 5055606000474.
It is an arithmetic number, because the mean of its divisors is an integer number (5055606000474).
Almost surely, 210111212000947 is an apocalyptic number.
10111212000947 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111212000947 is an equidigital number, since it uses as much as digits as its factorization.
10111212000947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 29.
The spelling of 10111212000947 in words is "ten trillion, one hundred eleven billion, two hundred twelve million, nine hundred forty-seven", and thus it is an aban number.
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