Base | Representation |
---|---|
bin | 10110111111010111111111… |
… | …111111101110010111010001 |
3 | 111021000020001111022121101212 |
4 | 112333113333333232113101 |
5 | 101223110110210311233 |
6 | 555014133334105505 |
7 | 30204052410226415 |
oct | 2677277777562721 |
9 | 437006044277355 |
10 | 101112120010193 |
11 | 2a243455838216 |
12 | b4102584ab295 |
13 | 4455aa7bb4486 |
14 | 1ad7bd1c16d45 |
15 | ba52592e9a48 |
hex | 5bf5fffee5d1 |
101112120010193 has 2 divisors, whose sum is σ = 101112120010194. Its totient is φ = 101112120010192.
The previous prime is 101112120010189. The next prime is 101112120010271. The reversal of 101112120010193 is 391010021211101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75311988349504 + 25800131660689 = 8678248^2 + 5079383^2 .
It is a cyclic number.
It is not a de Polignac number, because 101112120010193 - 22 = 101112120010189 is a prime.
It is not a weakly prime, because it can be changed into another prime (101112120010133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556060005096 + 50556060005097.
It is an arithmetic number, because the mean of its divisors is an integer number (50556060005097).
Almost surely, 2101112120010193 is an apocalyptic number.
It is an amenable number.
101112120010193 is a deficient number, since it is larger than the sum of its proper divisors (1).
101112120010193 is an equidigital number, since it uses as much as digits as its factorization.
101112120010193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 23.
Adding to 101112120010193 its reverse (391010021211101), we get a palindrome (492122141221294).
The spelling of 101112120010193 in words is "one hundred one trillion, one hundred twelve billion, one hundred twenty million, ten thousand, one hundred ninety-three".
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