1011121220221 has 4 divisors (see below), whose sum is σ = 1155567108832. Its totient is φ = 866675331612.

The previous prime is 1011121220177. The next prime is 1011121220227. The reversal of 1011121220221 is 1220221211101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011121220221 is a prime.

It is a super-2 number, since 2×1011121220221² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011121220195 and 1011121220204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011121220227) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72222944295 + ... + 72222944308.

It is an arithmetic number, because the mean of its divisors is an integer number (288891777208).

Almost surely, 2^{1011121220221} is an apocalyptic number.

It is an amenable number.

1011121220221 is a deficient number, since it is larger than the sum of its proper divisors (144445888611).

1011121220221 is an equidigital number, since it uses as much as digits as its factorization.

1011121220221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144445888610.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 1011121220221 its reverse (1220221211101), we get a palindrome (2231342431322).

The spelling of 1011121220221 in words is "one trillion, eleven billion, one hundred twenty-one million, two hundred twenty thousand, two hundred twenty-one".