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101112131302212 = 2238426010941851
BaseRepresentation
bin10110111111011000000000…
…101010110011001101000100
3111021000020002021120022010210
4112333120000222303031010
5101223110121103132322
6555014134420115420
730204052605216642
oct2677300052631504
9437006067508123
10101112131302212
112a243461150068
12b410260235b70
134455aaa339144
141ad7bd3516192
15ba525a2ca70c
hex5bf600ab3344

101112131302212 has 12 divisors (see below), whose sum is σ = 235928306371856. Its totient is φ = 33704043767400.

The previous prime is 101112131302201. The next prime is 101112131302229. The reversal of 101112131302212 is 212203131211101.

It is a tau number, because it is divible by the number of its divisors (12).

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4213005470914 + ... + 4213005470937.

Almost surely, 2101112131302212 is an apocalyptic number.

101112131302212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

101112131302212 is an abundant number, since it is smaller than the sum of its proper divisors (134816175069644).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101112131302212 is a wasteful number, since it uses less digits than its factorization.

101112131302212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8426010941858 (or 8426010941856 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 101112131302212 its reverse (212203131211101), we get a palindrome (313315262513313).

The spelling of 101112131302212 in words is "one hundred one trillion, one hundred twelve billion, one hundred thirty-one million, three hundred two thousand, two hundred twelve".

Divisors: 1 2 3 4 6 12 8426010941851 16852021883702 25278032825553 33704043767404 50556065651106 101112131302212