101112141130000 has 600 divisors, whose sum is σ = 331176421171904. Its totient is φ = 29091173760000.

The previous prime is 101112141129977. The next prime is 101112141130009. The reversal of 101112141130000 is 31141211101.

It is a super-3 number, since 3×101112141130000³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is not an unprimeable number, because it can be changed into a prime (101112141130009) by changing a digit.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 109650859 + ... + 110569141.

Almost surely, 2^{101112141130000} is an apocalyptic number.

101112141130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101112141130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (165588210585952).

101112141130000 is an abundant number, since it is smaller than the sum of its proper divisors (230064280041904).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101112141130000 is a wasteful number, since it uses less digits than its factorization.

101112141130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 918353 (or 918321 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 101112141130000 its reverse (31141211101), we get a palindrome (101143282341101).

The spelling of 101112141130000 in words is "one hundred one trillion, one hundred twelve billion, one hundred forty-one million, one hundred thirty thousand".