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10111220023 = 65531542991
BaseRepresentation
bin10010110101010110…
…01111100100110111
3222002200001012022111
421122223033210313
5131201433020043
64351154311451
7505364644402
oct113253174467
928080035274
1010111220023
11431957a293
121b62288587
13c51a5bc38
146bcc34d39
153e2a2c09d
hex25aacf937

10111220023 has 4 divisors (see below), whose sum is σ = 10112769568. Its totient is φ = 10109670480.

The previous prime is 10111219969. The next prime is 10111220039. The reversal of 10111220023 is 32002211101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10111220023 - 221 = 10109122871 is a prime.

It is a super-2 number, since 2×101112200232 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10111219985 and 10111220012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111220723) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 764943 + ... + 778048.

It is an arithmetic number, because the mean of its divisors is an integer number (2528192392).

Almost surely, 210111220023 is an apocalyptic number.

10111220023 is a deficient number, since it is larger than the sum of its proper divisors (1549545).

10111220023 is an equidigital number, since it uses as much as digits as its factorization.

10111220023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1549544.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10111220023 its reverse (32002211101), we get a palindrome (42113431124).

The spelling of 10111220023 in words is "ten billion, one hundred eleven million, two hundred twenty thousand, twenty-three".

Divisors: 1 6553 1542991 10111220023