1011122018 has 4 divisors (see below), whose sum is σ = 1516683030. Its totient is φ = 505561008.

The previous prime is 1011122017. The next prime is 1011122129. The reversal of 1011122018 is 8102211101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 659821969 + 351300049 = 25687^2 + 18743^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1011121987 and 1011122005.

It is not an unprimeable number, because it can be changed into a prime (1011122011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252780503 + ... + 252780506.

Almost surely, 2^1011122018 is an apocalyptic number.

1011122018 is a deficient number, since it is larger than the sum of its proper divisors (505561012).

1011122018 is an equidigital number, since it uses as much as digits as its factorization.

1011122018 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 505561011.

The product of its (nonzero) digits is 32, while the sum is 17.

The square root of 1011122018 is about 31798.1448829959. The cubic root of 1011122018 is about 1003.6936792688.

Adding to 1011122018 its reverse (8102211101), we get a palindrome (9113333119).

The spelling of 1011122018 in words is "one billion, eleven million, one hundred twenty-two thousand, eighteen".