Base | Representation |
---|---|
bin | 1001001100100011001110… |
… | …1100000110000110111001 |
3 | 1022210121211022200102121011 |
4 | 2103020303230012012321 |
5 | 2311130234333242103 |
6 | 33301010324113521 |
7 | 2062340314504504 |
oct | 223106354060671 |
9 | 38717738612534 |
10 | 10111220212153 |
11 | 3249165235625 |
12 | 11737572358a1 |
13 | 58463a3a5748 |
14 | 26d5583c413b |
15 | 128039219d6d |
hex | 93233b061b9 |
10111220212153 has 2 divisors, whose sum is σ = 10111220212154. Its totient is φ = 10111220212152.
The previous prime is 10111220212099. The next prime is 10111220212183. The reversal of 10111220212153 is 35121202211101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8898605200809 + 1212615011344 = 2983053^2 + 1101188^2 .
It is a cyclic number.
It is not a de Polignac number, because 10111220212153 - 29 = 10111220211641 is a prime.
It is not a weakly prime, because it can be changed into another prime (10111220212183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055610106076 + 5055610106077.
It is an arithmetic number, because the mean of its divisors is an integer number (5055610106077).
Almost surely, 210111220212153 is an apocalyptic number.
It is an amenable number.
10111220212153 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111220212153 is an equidigital number, since it uses as much as digits as its factorization.
10111220212153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 10111220212153 its reverse (35121202211101), we get a palindrome (45232422423254).
The spelling of 10111220212153 in words is "ten trillion, one hundred eleven billion, two hundred twenty million, two hundred twelve thousand, one hundred fifty-three".
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