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101112220111 = 714444602873
BaseRepresentation
bin101111000101011000…
…0100000100111001111
3100122222200110222102011
41132022300200213033
53124034212020421
6114241133442051
710206440455510
oct1361260404717
9318880428364
10101112220111
1139977237581
121771a340327
1396c507b656
144c72a60a07
15296bbd64e1
hex178ac209cf

101112220111 has 4 divisors (see below), whose sum is σ = 115556822992. Its totient is φ = 86667617232.

The previous prime is 101112220087. The next prime is 101112220141. The reversal of 101112220111 is 111022211101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 101112220111 - 215 = 101112187343 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101112220091 and 101112220100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101112220141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7222301430 + ... + 7222301443.

It is an arithmetic number, because the mean of its divisors is an integer number (28889205748).

Almost surely, 2101112220111 is an apocalyptic number.

101112220111 is a deficient number, since it is larger than the sum of its proper divisors (14444602881).

101112220111 is an equidigital number, since it uses as much as digits as its factorization.

101112220111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14444602880.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 101112220111 its reverse (111022211101), we get a palindrome (212134431212).

The spelling of 101112220111 in words is "one hundred one billion, one hundred twelve million, two hundred twenty thousand, one hundred eleven".

Divisors: 1 7 14444602873 101112220111