101113030313 has 2 divisors, whose sum is σ = 101113030314. Its totient is φ = 101113030312.

The previous prime is 101113030297. The next prime is 101113030349. The reversal of 101113030313 is 313030311101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66124579609 + 34988450704 = 257147^2 + 187052^2 .

It is a cyclic number.

It is not a de Polignac number, because 101113030313 - 2⁴ = 101113030297 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101113030291 and 101113030300.

It is not a weakly prime, because it can be changed into another prime (101113030363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556515156 + 50556515157.

It is an arithmetic number, because the mean of its divisors is an integer number (50556515157).

Almost surely, 2^101113030313 is an apocalyptic number.

It is an amenable number.

101113030313 is a deficient number, since it is larger than the sum of its proper divisors (1).

101113030313 is an equidigital number, since it uses as much as digits as its factorization.

101113030313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 101113030313 its reverse (313030311101), we get a palindrome (414143341414).

The spelling of 101113030313 in words is "one hundred one billion, one hundred thirteen million, thirty thousand, three hundred thirteen".