101113032022 has 4 divisors (see below), whose sum is σ = 151669548036. Its totient is φ = 50556516010.

The previous prime is 101113032019. The next prime is 101113032049. The reversal of 101113032022 is 220230311101.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 101113031987 and 101113032005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25278258004 + ... + 25278258007.

It is an arithmetic number, because the mean of its divisors is an integer number (37917387009).

Almost surely, 2^101113032022 is an apocalyptic number.

101113032022 is a deficient number, since it is larger than the sum of its proper divisors (50556516014).

101113032022 is an equidigital number, since it uses as much as digits as its factorization.

101113032022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50556516013.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 101113032022 its reverse (220230311101), we get a palindrome (321343343123).

The spelling of 101113032022 in words is "one hundred one billion, one hundred thirteen million, thirty-two thousand, twenty-two".